Optimal. Leaf size=111 \[ -\frac{\cos \left (\frac{a}{b}\right ) \text{CosIntegral}\left (\frac{a+b \sin ^{-1}(c x)}{b}\right )}{2 b^3 c}-\frac{\sin \left (\frac{a}{b}\right ) \text{Si}\left (\frac{a+b \sin ^{-1}(c x)}{b}\right )}{2 b^3 c}+\frac{x}{2 b^2 \left (a+b \sin ^{-1}(c x)\right )}-\frac{\sqrt{1-c^2 x^2}}{2 b c \left (a+b \sin ^{-1}(c x)\right )^2} \]
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Rubi [A] time = 0.172366, antiderivative size = 111, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.6, Rules used = {4621, 4719, 4623, 3303, 3299, 3302} \[ -\frac{\cos \left (\frac{a}{b}\right ) \text{CosIntegral}\left (\frac{a+b \sin ^{-1}(c x)}{b}\right )}{2 b^3 c}-\frac{\sin \left (\frac{a}{b}\right ) \text{Si}\left (\frac{a+b \sin ^{-1}(c x)}{b}\right )}{2 b^3 c}+\frac{x}{2 b^2 \left (a+b \sin ^{-1}(c x)\right )}-\frac{\sqrt{1-c^2 x^2}}{2 b c \left (a+b \sin ^{-1}(c x)\right )^2} \]
Antiderivative was successfully verified.
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Rule 4621
Rule 4719
Rule 4623
Rule 3303
Rule 3299
Rule 3302
Rubi steps
\begin{align*} \int \frac{1}{\left (a+b \sin ^{-1}(c x)\right )^3} \, dx &=-\frac{\sqrt{1-c^2 x^2}}{2 b c \left (a+b \sin ^{-1}(c x)\right )^2}-\frac{c \int \frac{x}{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^2} \, dx}{2 b}\\ &=-\frac{\sqrt{1-c^2 x^2}}{2 b c \left (a+b \sin ^{-1}(c x)\right )^2}+\frac{x}{2 b^2 \left (a+b \sin ^{-1}(c x)\right )}-\frac{\int \frac{1}{a+b \sin ^{-1}(c x)} \, dx}{2 b^2}\\ &=-\frac{\sqrt{1-c^2 x^2}}{2 b c \left (a+b \sin ^{-1}(c x)\right )^2}+\frac{x}{2 b^2 \left (a+b \sin ^{-1}(c x)\right )}-\frac{\operatorname{Subst}\left (\int \frac{\cos \left (\frac{a}{b}-\frac{x}{b}\right )}{x} \, dx,x,a+b \sin ^{-1}(c x)\right )}{2 b^3 c}\\ &=-\frac{\sqrt{1-c^2 x^2}}{2 b c \left (a+b \sin ^{-1}(c x)\right )^2}+\frac{x}{2 b^2 \left (a+b \sin ^{-1}(c x)\right )}-\frac{\cos \left (\frac{a}{b}\right ) \operatorname{Subst}\left (\int \frac{\cos \left (\frac{x}{b}\right )}{x} \, dx,x,a+b \sin ^{-1}(c x)\right )}{2 b^3 c}-\frac{\sin \left (\frac{a}{b}\right ) \operatorname{Subst}\left (\int \frac{\sin \left (\frac{x}{b}\right )}{x} \, dx,x,a+b \sin ^{-1}(c x)\right )}{2 b^3 c}\\ &=-\frac{\sqrt{1-c^2 x^2}}{2 b c \left (a+b \sin ^{-1}(c x)\right )^2}+\frac{x}{2 b^2 \left (a+b \sin ^{-1}(c x)\right )}-\frac{\cos \left (\frac{a}{b}\right ) \text{Ci}\left (\frac{a+b \sin ^{-1}(c x)}{b}\right )}{2 b^3 c}-\frac{\sin \left (\frac{a}{b}\right ) \text{Si}\left (\frac{a+b \sin ^{-1}(c x)}{b}\right )}{2 b^3 c}\\ \end{align*}
Mathematica [A] time = 0.417795, size = 93, normalized size = 0.84 \[ -\frac{\frac{b \left (\frac{b \sqrt{1-c^2 x^2}}{c}-x \left (a+b \sin ^{-1}(c x)\right )\right )}{\left (a+b \sin ^{-1}(c x)\right )^2}+\frac{\cos \left (\frac{a}{b}\right ) \text{CosIntegral}\left (\frac{a}{b}+\sin ^{-1}(c x)\right )}{c}+\frac{\sin \left (\frac{a}{b}\right ) \text{Si}\left (\frac{a}{b}+\sin ^{-1}(c x)\right )}{c}}{2 b^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.03, size = 138, normalized size = 1.2 \begin{align*}{\frac{1}{c} \left ( -{\frac{1}{2\, \left ( a+b\arcsin \left ( cx \right ) \right ) ^{2}b}\sqrt{-{c}^{2}{x}^{2}+1}}-{\frac{1}{ \left ( 2\,a+2\,b\arcsin \left ( cx \right ) \right ){b}^{3}} \left ( \arcsin \left ( cx \right ){\it Si} \left ( \arcsin \left ( cx \right ) +{\frac{a}{b}} \right ) \sin \left ({\frac{a}{b}} \right ) b+\arcsin \left ( cx \right ){\it Ci} \left ( \arcsin \left ( cx \right ) +{\frac{a}{b}} \right ) \cos \left ({\frac{a}{b}} \right ) b+{\it Si} \left ( \arcsin \left ( cx \right ) +{\frac{a}{b}} \right ) \sin \left ({\frac{a}{b}} \right ) a+{\it Ci} \left ( \arcsin \left ( cx \right ) +{\frac{a}{b}} \right ) \cos \left ({\frac{a}{b}} \right ) a-xbc \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{b c x \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) + a c x - \sqrt{c x + 1} \sqrt{-c x + 1} b -{\left (b^{4} c \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )^{2} + 2 \, a b^{3} c \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) + a^{2} b^{2} c\right )} \int \frac{1}{b^{3} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) + a b^{2}}\,{d x}}{2 \,{\left (b^{4} c \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )^{2} + 2 \, a b^{3} c \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) + a^{2} b^{2} c\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{1}{b^{3} \arcsin \left (c x\right )^{3} + 3 \, a b^{2} \arcsin \left (c x\right )^{2} + 3 \, a^{2} b \arcsin \left (c x\right ) + a^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (a + b \operatorname{asin}{\left (c x \right )}\right )^{3}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.42593, size = 651, normalized size = 5.86 \begin{align*} -\frac{b^{2} \arcsin \left (c x\right )^{2} \cos \left (\frac{a}{b}\right ) \operatorname{Ci}\left (\frac{a}{b} + \arcsin \left (c x\right )\right )}{2 \,{\left (b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c\right )}} - \frac{b^{2} \arcsin \left (c x\right )^{2} \sin \left (\frac{a}{b}\right ) \operatorname{Si}\left (\frac{a}{b} + \arcsin \left (c x\right )\right )}{2 \,{\left (b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c\right )}} + \frac{b^{2} c x \arcsin \left (c x\right )}{2 \,{\left (b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c\right )}} - \frac{a b \arcsin \left (c x\right ) \cos \left (\frac{a}{b}\right ) \operatorname{Ci}\left (\frac{a}{b} + \arcsin \left (c x\right )\right )}{b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c} - \frac{a b \arcsin \left (c x\right ) \sin \left (\frac{a}{b}\right ) \operatorname{Si}\left (\frac{a}{b} + \arcsin \left (c x\right )\right )}{b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c} + \frac{a b c x}{2 \,{\left (b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c\right )}} - \frac{a^{2} \cos \left (\frac{a}{b}\right ) \operatorname{Ci}\left (\frac{a}{b} + \arcsin \left (c x\right )\right )}{2 \,{\left (b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c\right )}} - \frac{a^{2} \sin \left (\frac{a}{b}\right ) \operatorname{Si}\left (\frac{a}{b} + \arcsin \left (c x\right )\right )}{2 \,{\left (b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c\right )}} - \frac{\sqrt{-c^{2} x^{2} + 1} b^{2}}{2 \,{\left (b^{5} c \arcsin \left (c x\right )^{2} + 2 \, a b^{4} c \arcsin \left (c x\right ) + a^{2} b^{3} c\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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